# Models of Heptominoes and Heptacubes

With the 36 clipped tetracubes you can try to construct heptomino models three times as wide and two
times as high with 7x3x3x2 = 126 = 3.5*36 unit cubes. As an example I built the latin cross and
the hetomino with the hole. The 2x3x21 solid box is another example.

The total volume of the 32 extended tricubes is 32*3.5=112 = 2*7*8. Therefore two duplications of
some or all? heptacubes may be possible. Two out of 1023 problems are solved here.

Drawings showing the layers of the constructions.
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